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+// Chapter8
+// Page.No-264
+// Example8_2
+// Figure 8.4
+// Power dissipation for Q1
+// Page.No-264
+// Example_8_2
+// Figure 8.4
+// Given
+clear;clc;
+Vl=11.7;            //in V
+Rl=20;           //in Ohm
+Il=Vl/Rl;
+printf("\n Output Load Current Il is = %.3f A \n",Il); // Result
+Vc=20; Ve=11.7;     //in V
+Vce=Vc-Ve;
+printf("\n Output Load Voltage Vce is = %.2f V\n",Vce); // Result
+Pd=Il*Vce;
+printf("\n Power dissiption Pd is = %.2f W \n",Pd); // Result
+Ib=0.020;                   //in Amp
+B=Il/Ib;
+printf("\n Beta is = %.2f  \n",B); // Result
+Pl=Il*Vl;
+printf("\n Power dissiption across load ,Pl is = %.3f W \n",Pl); // Result
+Vin=20;             //in V
+Pin=Il*Vin;         //Iin=Il
+printf("\n Input Power dissiption ,Pin is = %.2f W \n",Pin); // Result
+n=Pl/Pin;
+printf("\n Efficiency   is = %.3f or %.1f  percent \n",n,n*100); // Result