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+// Chapter 1
+//page 34
+//Example no 1-18
+//figure 1.19
+//tail current 
+//Given
+clc;
+Vcc=20;     //in Volt
+Rc=3000;        //in Ohm
+Rb=5000;        //in ohm
+Rt=2000;        //in Ohm
+Vee=10;        //in Volt
+It=(Vee-0.7)/Rt;
+printf("\n It =%.5f Amp\n ",It);// Result
+//Ie1=Ie2=It/2
+Ic=It/2;
+Vc=Vcc-Ic*Rc;
+printf("\n Collector voltage is %.3f V\n ",Vc);// Result
+B=100;      //Assumumption
+Ib=Ic/B;
+printf("\n Ib %.8f Amp\n ",Ib);// Result
+Vb=-Ib*Rb;
+printf("\n Base Voltage %.5f V\n ",Vb);// Result
+
+