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+//Variable declaration:
+Do = 2.5/100 //Outside diameter of tube (m)
+t = 1/10**3 //Thickness of fin (m)
+T = 25 //Fluid temperature ( C)
+Tb = 170 //Surface temperature ( C)
+h = 130 //Heat transfer coefficient (W/m^2.K)
+k = 200 //Thermal conductivity of fin (W/m.K)
+rf = 2.75/100 //Outside radius of fin (m)
+
+//Calculation:
+ro = Do/2 //Radius of tube (m)
+Ab = 2*%pi*ro*t //Area of the base of the fin (m^2)
+Te = Tb-T //Excess temperature at the base of the fin (K)
+Q1 = h*Ab*Te //Total heat transfer rate without the fin (W)
+Bi = h*(t/2)/k //Biot number
+L = rf-ro //Fin height (m)
+rc = rf+t/2 //Corrected radius (m)
+Lc = L+t/2 //Corrected height (m)
+Ap = Lc*t //Profile area (m^2)
+Af = 2*%pi*(rc**2-ro**2) //Fin surface area (m^2)
+Qm = h*Af*Te //Maximum fin heat transfer rate (W)
+A = sqrt(Lc**3*h/(k*Ap)) //Abscissa of fin efficiency
+C = rf/ro //Curve parameter of fin efficiency
+//From figure 17.4:
+nf = 0.86 //Fin efficiency
+Qf = nf*Qm //Fin heat transfer rate (W)
+R = Te/Qf //Fin resistance (K/W)
+
+//Result:
+printf("1. The heat transfer rate without the fin is : %.2f W .",Q1)
+printf("Or, the heat transfer rate without the fin is : %.0f Btu/h .",Q1*3.412)
+printf("2. The corrected length is : %.4f m .",Lc)
+printf("3. The outer radius is : %.3f m ",rc)
+printf("4. The maximum heat transfer rate from the fin is : %.2f W .",Qm)
+printf("5. The fin efficiency is : %.0f %%",nf*100)
+printf("6. The fin heat transfer rate is : %.0f %%",Qf)
+printf("Or, the fin heat transfer rate is : %.0f %%",Qf*3.412)
+printf("7. The fin thermal resistance is : %.2f K/W .",R)