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+clc
+clear
+printf("Example 9.11 | Page number 283 \n\n");
+//Evaluate the mass fraction and volumes fractions of N2 and H2 in mixture
+//Given data
+R = 1841 //J/kgK //Gas constant
+Cp = 6310 //J/kgK //specific heat at constant pressure
+MN = 28 //kg/kmol //molar mass N2
+MH = 2 //kg/kmol //molar mass H2
+CpN = 1042 //J/kgK //specific heat of N2
+CpH = 14210 //J/kgK //specific heat of H2
+
+//Solution
+Y = [8314.3/MN, 8314.3/MH;CpN, CpH]\[R; Cp]
+YN = Y(1) //mass fraction of N2
+YH = Y(2) //mass fraction of H2
+XN = YN*(8314.3/(R*MN)) //volume fraction of N2
+XH = YH*(8314.3/(R*MH)) //volume fraction of H2
+printf("Mass fraction of N2 = %.1f \n",YN)
+printf("Mass fraction of H2 = %.1f \n",YH)
+printf("Volume fraction of N2 = %.4f \n",XN)
+printf("Volume fraction of H2 = %.4f \n",XH)