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+// Exa 3.11
+clc;
+clear;
+close;
+format('v',6)
+// Given data
+I_Z = 0.2;// in A
+R = 10;// in ohm
+V_Z = 8 + (R*I_Z);// in V
+I_Lmin = V_Z/R;// in A
+I_Zmax = 0.2;//in A
+Vimax = 15;// in V
+// The minimum value of R
+Rimin = (Vimax-V_Z)/(I_Zmax+I_Lmin);// in ohm
+disp(Rimin,"The minimum value of R in ohm is");
+
+// Note: The calculation in the book is not accurate, So the answer in the book is not accurate.