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+// Exa 8.9
+format('v',6)
+clc;
+clear;
+close;
+// Given data
+R_C= 1;// in k ohm
+V_CC= 5;// in V
+V_CEsat= 0;// in V
+V_BE= 0.7;// in V
+bita_min= 50;
+bita_max= 100;
+// For the transistor to go to saturation,
+I_C= (V_CC-V_CEsat)/R_C;// in mA
+bita= bita_min;// for driving the transistor into saturation
+I_Bmin= I_C/bita;//minimum base current in mA
+// So, (V_CC-V_BE)/R_B >= I_B or
+R_B= (V_CC-V_BE)/I_Bmin;// in k ohm
+disp(R_B,"The maximum permissible value of R_B in k ohm is : ")
+// For actual calculation one may take V_CEsat= 0.3 V
+V_CEsat= 0.3;// in V
+I_C= (V_CC-V_CEsat)/R_C;// in mA
+bita= bita_min;// for driving the transistor into saturation
+I_Bmin= I_C/bita;//minimum base current in mA
+// So, (V_CC-V_BE)/R_B >= I_B or
+R_B= (V_CC-V_BE)/I_Bmin;// in k ohm
+disp("For actual calculation at V_CE(sat) = 0.3 V, the maximum value ")
+disp(R_B,"of R_B in k ohm is : ")