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-rwxr-xr-x249/CH7/EX7.1/7_01.sce4
-rwxr-xr-x249/CH7/EX7.2/7_02.sce33
-rwxr-xr-x249/CH7/EX7.3/7_03.sce28
-rwxr-xr-x249/CH7/EX7.4/7_04.sce13
4 files changed, 78 insertions, 0 deletions
diff --git a/249/CH7/EX7.1/7_01.sce b/249/CH7/EX7.1/7_01.sce
new file mode 100755
index 000000000..1551ebddb
--- /dev/null
+++ b/249/CH7/EX7.1/7_01.sce
@@ -0,0 +1,4 @@
+clear
+clc
+//Theorotical Questions
+printf("Its a theorotical Question") \ No newline at end of file
diff --git a/249/CH7/EX7.2/7_02.sce b/249/CH7/EX7.2/7_02.sce
new file mode 100755
index 000000000..95d7ea47e
--- /dev/null
+++ b/249/CH7/EX7.2/7_02.sce
@@ -0,0 +1,33 @@
+clear
+clc
+//Initial Concentration(mol/litre)eactant in combined feed
+CAo=10;CBo=10;
+//For 90% Conversion
+XA=0.9;
+CAf=CAo*(1-XA);
+//Instantaneous fractional yield of desired compound is
+//Q(R/A)=dCR/(dCR+dCS)=CA/(CA+CB^1.5)
+//But CA=CB so Q(R/A)=CA/(CA+CA^1.5)
+//For Plug Flow
+//Overall Fractional Yield(Qp)is
+CA=CAf;
+Qp=(-1/(CAo-CAf))*integrate('1/(1+CA^0.5)','CA',CAo,CAf);
+CRf=9*Qp;
+printf("\n Part a")
+printf("\n For Plug Flow")
+printf("\n Concentration of R(mol/litre) in the product stream is %f \n",CRf)
+//Mixed Flow
+//Overall Fractional Yield(Qm)is
+Qm=CA/(CA+CA^1.5);
+CRf=9*Qm;
+printf("\n Part b")
+printf("\n For Mixed Flow")
+printf("\n Concentration of R(mol/litre) in the product stream is %f \n",CRf)
+//Plug flow A,Mixed flow B
+CAo=19;CB=1;
+Q=-1/(CAo-CAf)*integrate('CA/(CA+CB^1.5)','CA',CAo,CAf);
+CRf=9*Q;
+printf("\n Part c")
+printf("\n For Plug flow A,Mixed flow B")
+printf("\n Concentration of R(mol/litre) in the product stream is %f \n",CRf)
+disp('The result for plug flow varies as there seems to be typographical error in integration done in book') \ No newline at end of file
diff --git a/249/CH7/EX7.3/7_03.sce b/249/CH7/EX7.3/7_03.sce
new file mode 100755
index 000000000..b404c196e
--- /dev/null
+++ b/249/CH7/EX7.3/7_03.sce
@@ -0,0 +1,28 @@
+clear
+clc
+CAo=2;
+//Since S is the desired Product
+//Q(S/A)=2CA/(1+CA)^2
+//Part a
+//Csf=(CAo-CA)*2*CA/(1+CA)^2
+//on differentiating this to get max Csf,we get max value at
+CA=0.5;
+Csf=(CAo-CA)*2*CA/(1+CA)^2;
+printf("\n Part a")
+printf("\n For Mixed Flow Reactor")
+printf("\n Maximum expected Cs is %f",Csf)
+//For Plug Flow Reactor
+//Production of s is max at 100% Conversion of A
+CAf=0;
+Csf=-1*integrate('2*CA/(1+CA)^2','CA',CAo,CAf);
+printf("\n Part b")
+printf("\n For Plug Flow")
+printf("\n Maximum expected concentration of S is %f \n",Csf)
+//Part C
+//Since no reactant leaves the system unconverted,what is important is to operate at condition of highest fractional yield
+//ie. at CA=1 where Q(S/A)=0.5
+CA=1;
+Csf=(CAo-CA)*2*CA/(1+CA)^2;
+printf("Part c")
+printf("\n For MFR with separation and recycle" )
+printf("\n Concentration of Csf is %f",Csf) \ No newline at end of file
diff --git a/249/CH7/EX7.4/7_04.sce b/249/CH7/EX7.4/7_04.sce
new file mode 100755
index 000000000..35b037ce8
--- /dev/null
+++ b/249/CH7/EX7.4/7_04.sce
@@ -0,0 +1,13 @@
+clear
+clc
+//Mixed flow followed by plug flow would be best
+//From ex 7.3
+//For mixed flow
+CAo=2;CA=1;Q=0.5;
+Cs1=Q*(CAo-CA);
+//For plug flow
+Cs2=-1*integrate('2*CA/(1+CA)^2','CA',1,0);
+//Total amount of CS formed is
+Cs=Cs1+Cs2;
+printf("Mixed flow followed by plug flow would be best")
+printf("\n Total amount of CS formed(mol/litre) is %f \n",Cs) \ No newline at end of file