diff options
Diffstat (limited to '2471/CH3')
-rwxr-xr-x | 2471/CH3/EX3.14/Ex3_14.sce | 117 |
1 files changed, 64 insertions, 53 deletions
diff --git a/2471/CH3/EX3.14/Ex3_14.sce b/2471/CH3/EX3.14/Ex3_14.sce index 84b34e6bd..c897eb5cb 100755 --- a/2471/CH3/EX3.14/Ex3_14.sce +++ b/2471/CH3/EX3.14/Ex3_14.sce @@ -1,53 +1,64 @@ -clear ;
-clc;
-// Example 3.14
-printf('Example 3.14\n\n');
-printf('Page No. 74\n\n');
-
-// given
-n = 5;//years
-C = 80000;// Cost of the project in Pound
-Cash_in = [10000 20000 30000 40000 50000]// Cash inflow in Pound
-r_d1 = 15;// Discount factor of 15%
-r_d2 = 18 ;// Discount factor of 18%
-r_d3 = 20;// Discount factor of 20%
-
-//At discount of 15%
-df_1 = [0.870 0.756 0.658 0.572 0.497]// Discount factor for every year
-PV_1 = [8700 15120 19740 22880 24850]// Present value
-Net_1 = sum (PV_1);// net present value
-
-
-//At discount of 18%
-df_2 = [0.847 0.718 0.609 0.516 0.437]// Discount factor for every year
-PV_2 = [8470 14360 18270 20640 21850]// Present value
-Net_2 = sum (PV_2);// net present value
-
-
-//At discount of 20%
-df_3 = [0.833 0.694 0.579 0.482 0.402]// Discount factor for every year
-PV_3 = [8330 13880 17370 19280 20100]// Present value
-Net_3 = sum (PV_3);// net present value
-
-// f = N.P.V. cash inflow - N.P.V. cash outflow
-//(1) By Numerical Method
-ff = 2*((sum (PV_2) - C)/(sum (PV_2) - sum(PV_3)));// in percentage
-f = 18 + ff;
-printf('the internal rate of return in percentage is %3.2f \n\n',f)// Deviation in answer due to direct substitution
-
-//(2) By Graphical Interpolation
-f_1 = (sum (PV_1) - C)/10^3;//At discount factor of 15%
-f_2 = (sum (PV_2) - C)/10^3;//At discount factor of 18%
-f_3 = (sum (PV_3) - C)/10^3;//At discount factor of 20%
-
-x = [f_1 f_2 f_3];
-y = [r_d1 r_d2 r_d3];
-plot(x,y,'r*');
-
-plot2d (x,y);// please see the corresponding graph in graphic window
-xtitle('Discount factor against f','f ( *10^3 Pound)','Discount factor(%)')
-regress(x,y)
-coefs = regress(x,y);
-printf('the internal rate of return in percentage is %3.1f \n',coefs(1))// Deviation in answer due to direct substitution
-
-
+clear ; +clc; +function [coefs]=regress(x,y) +coefs=[] + if (type(x) <> 1)|(type(y)<>1) then error(msprintf(gettext("%s: Wrong type for input arguments: Numerical expected.\n"),"regress")), end + lx=length(x) + if lx<>length(y) then error(msprintf(gettext("%s: Wrong size for both input arguments: same size expected.\n"),"regress")), end + if lx==0 then error(msprintf(gettext("%s: Wrong size for input argument #%d: Must be > %d.\n"),"regress", 1, 0)), end + x=matrix(x,lx,1) + y=matrix(y,lx,1) + xbar=sum(x)/lx + ybar=sum(y)/lx + coefs(2)=sum((x-xbar).*(y-ybar))/sum((x-xbar).^2) + coefs(1)=ybar-coefs(2)*xbar +endfunction +// Example 3.14 +printf('Example 3.14\n\n'); +printf('Page No. 74\n\n'); + +// given +n = 5;//years +C = 80000;// Cost of the project in Pound +Cash_in = [10000 20000 30000 40000 50000]// Cash inflow in Pound +r_d1 = 15;// Discount factor of 15% +r_d2 = 18 ;// Discount factor of 18% +r_d3 = 20;// Discount factor of 20% + +//At discount of 15% +df_1 = [0.870 0.756 0.658 0.572 0.497]// Discount factor for every year +PV_1 = [8700 15120 19740 22880 24850]// Present value +Net_1 = sum (PV_1);// net present value + + +//At discount of 18% +df_2 = [0.847 0.718 0.609 0.516 0.437]// Discount factor for every year +PV_2 = [8470 14360 18270 20640 21850]// Present value +Net_2 = sum (PV_2);// net present value + + +//At discount of 20% +df_3 = [0.833 0.694 0.579 0.482 0.402]// Discount factor for every year +PV_3 = [8330 13880 17370 19280 20100]// Present value +Net_3 = sum (PV_3);// net present value + +// f = N.P.V. cash inflow - N.P.V. cash outflow +//(1) By Numerical Method +ff = 2*((sum (PV_2) - C)/(sum (PV_2) - sum(PV_3)));// in percentage +f = 18 + ff; +printf('the internal rate of return in percentage is %3.2f \n\n',f)// Deviation in answer due to direct substitution + +//(2) By Graphical Interpolation +f_1 = (sum (PV_1) - C)/10^3;//At discount factor of 15% +f_2 = (sum (PV_2) - C)/10^3;//At discount factor of 18% +f_3 = (sum (PV_3) - C)/10^3;//At discount factor of 20% + +x = [f_1 f_2 f_3]; +y = [r_d1 r_d2 r_d3]; +plot(x,y,'r*'); + +plot2d (x,y);// please see the corresponding graph in graphic window +xtitle('Discount factor against f','f ( *10^3 Pound)','Discount factor(%)') +regress(x,y) +coefs = regress(x,y); +printf('the internal rate of return in percentage is %3.1f \n',coefs(1))// Deviation in answer due to direct substitution
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