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+clear ;
+clc;
+// Example 3.8
+printf('Example 3.8\n\n');
+printf('Page No. 69\n\n');
+
+//Refer figure 3.6
+// given
+n = 5;//years
+C = 80000;// COst of the project in Pound
+S = 0;// Zero Salvage Value
+A_E = [10000 20000 30000 40000 50000]// Annual Net cash flow for project E in Pound
+C_E = [10000 30000 60000 100000 150000]// Cummulative Net cash flow for project E in Pound
+A_F = [50000 40000 30000 20000 10000]// Annual Net cash flow for project F in Pound
+C_F = [50000 90000 120000 140000 150000]// Cummulative Net cash flow for project F in Pound
+
+//From the figure 3.6 (intercept of x-axis)
+P_F = 1.75;// in years
+P_E = 3.5;// in years
+printf('The pay-back time of project F is %.2f \n',P_F)
+printf('The pay-back time of project E is %.1f \n\n',P_E)
+
+printf('As the pay-back time is less for project F,\nProject F would always be choosen in practice\nsince prediction of savings in the early years are more reliable than long-term predictions.')