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+
+clc;
+// Example 1.1
+printf('Example 1.1\n\n');
+printf(' Page No. 08\n\n');
+// Solution
+
+// Given
+m1= 40*10^3;// fuel oil in gallons per year
+ga= 4.545*10^-3;// m^3
+m= m1*ga;// fuel oil in m^3 per year
+Cv1= 175*10^3;// Btu per gallons
+Bt= .2321*10^6;// J per m^3
+Cv= Cv1*Bt;// in J per year per m^3
+q=m*Cv;// in J per year
+printf(' Heat available is %3.2e J per year\n',q)