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-//Chapter-3,Example 19,Page 62
-clc;
-close;
-
-energy= (100*10^6)*24*3600    //energy comsumed in city in a day in Joule
-
-efcy=20/100   //efficiency of reactor
-
-energy_r = energy/efcy    //energy required per day
-
-energy_rl=200*1.6*10^-13   //energy released per nuclide
-
-n = energy_r/energy_rl    //number of U(235) to be fissioned 
-
-//6.023*10^26 atoms of U(235) are present in 235 kg
-//n  atoms of U(235) are present in
-
-m=235*n/(6.023*10^26)
-
-printf('the amount of fule required for one day operation is %.2f kg',m)