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+//Chapter-18,Example 6,Page 407
+clc();
+close();
+
+CO =0.46   //composition of CO
+
+CH4 =0.1   //composition of CH4
+
+H2 =0.4   //composition of H2
+
+C2H2 =0.02   //composition of C2H2
+
+N2=0.01   //composition of N2
+
+//for reaction CO + (1/2)O2  = CO2
+
+V1=CO*(1/2)   //volume of O2 required
+
+//for reaction CH4 + 2O2  = CO2 + 2H2O
+
+V2=CH4*2   //volume of O2 required
+
+//for reaction H2 + (1/2)O2 = H2O
+
+V3=H2*(1/2)   //volume of O2 required
+
+//for reaction C2H2 + (5/2)O2 = 2CO2 +H2O
+
+V4=C2H2*(5/2)   //volume of O2 required
+
+total_v= V1+V2+V3+V4
+
+//as air contains 21% of O2 by volume
+
+V_air = total_v*100/21   //volume of air 
+
+printf("the volume of air required is %.3f cubicmeter",V_air)