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+//Chapter-17,Example 6,Page 371
+clc();
+close();
+
+v= 10^6  //volume of water
+
+m1 = 40  //mass of Ca+2
+
+m2 = 24    //mass of Mg+2
+
+m3 = 44    //mass of CO2
+
+m4 = 122    //mass of HCO3-
+
+amnt_1 = 20     //amount of Ca+2 in ppm
+
+amnt_2 = 25     //amount of Mg+2 in ppm
+
+amnt_3 = 30     //amount of CO2 in ppm 
+
+amnt_4 = 150     //amount of HCO3- in ppm
+
+lime_1 = (74/100)*[(amnt_2*100/m2)+(amnt_3*100/m3)+(amnt_4*100/m4)]*v
+
+soda = (106/100)*[(amnt_1*100/m1)+(amnt_2*100/m2)-(amnt_4*100/m4)]*v
+
+printf("the lime required is = %.3f mg",lime_1)
+
+printf("\n the soda required is = %.3f mg",soda)