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+//Chapter-17,Example 4,Page 370
+clc();
+close();
+
+m1 = 146    //mass of Mg(HCO3)2
+
+m2 = 162    //mass of Ca(HCO3)2
+
+m3 = 111    //mass of CaCl2
+
+m4 = 120    //mass of MgSO4
+
+m5 = 136    //mass of CaSO4
+
+amnt_1 = 12.5     //amount of Mg(HCO3)2 in ppm
+
+amnt_2 = 10.5     //amount of Ca(HCO3)2 in ppm
+
+amnt_3 = 8.2     //amount of CaCl2 in ppm 
+
+amnt_4 = 2.6     //amount of MgSO4 in ppm
+
+amnt_5 = 7.5     //amount of CaSO4 in ppm
+
+temp_hard= (amnt_1*100/m1)+(amnt_2*100/m2)
+
+perm_hard= (amnt_3*100/m3)+(amnt_4*100/m4)+(amnt_5*100/m5)
+
+total= temp_hard +perm_hard
+
+printf("the temporary hardness is = %.3f mg/l",temp_hard)
+
+printf("\n the permanent hardness is = %.3f mg/l",perm_hard)
+
+printf("\n the total  hardness is = %.3f mg/l",total)
+
+v= 100    //volume of sample
+
+v_EDTA = total*v/1000   //volume of EDTA 
+
+printf("\n the volume of M/100 EDTA required is = %.3f ml",v_EDTA)