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+//Chapter-17,Example 2,Page 369
+clc();
+close();
+
+m1= 136 // mass of FeSO4
+
+m2 = 100 //mass of CaCO3
+
+//for 100 ppm hardness FeSO4 required per 10^6 parts of water is 136 parts
+//for 200 ppm hardness
+
+amt= m1*200/m2
+
+printf("the amount of FeSO4 required is = %.f mg/l",amt)