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+//chapter9
+//example9.17
+//page160
+
+Vin=240 // V rms
+Rl=480 // ohm
+rf=1 // ohm
+
+Vm=Vin*2^0.5
+// for bridge rectifier we know that
+Im=Vm/(2*rf+Rl)
+Idc=2*Im/%pi
+Irms=Im/2
+P=Irms^2*rf
+
+printf("mean load current = %.3f A \n",Idc)
+printf("power dissipated in each diode = %.3f W \n",P)
+
+// the accurate answers are mean load current = 0.448 A and power dissipated in each diode = 0.124 W