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Diffstat (limited to '2459/CH9/EX9.10')
| -rw-r--r-- | 2459/CH9/EX9.10/Ex9_10.PNG | bin | 0 -> 5576 bytes | |||
| -rw-r--r-- | 2459/CH9/EX9.10/Ex9_10.sce | 21 |
2 files changed, 21 insertions, 0 deletions
diff --git a/2459/CH9/EX9.10/Ex9_10.PNG b/2459/CH9/EX9.10/Ex9_10.PNG Binary files differnew file mode 100644 index 000000000..b8d53caa3 --- /dev/null +++ b/2459/CH9/EX9.10/Ex9_10.PNG diff --git a/2459/CH9/EX9.10/Ex9_10.sce b/2459/CH9/EX9.10/Ex9_10.sce new file mode 100644 index 000000000..10b306ed8 --- /dev/null +++ b/2459/CH9/EX9.10/Ex9_10.sce @@ -0,0 +1,21 @@ +//chapter9
+//example9.10
+//page152
+
+n=10
+Vp=230 // V
+
+Vpm=2^0.5*Vp
+Vsm=Vpm/n // since n=Vpm/Vsm=N1/N2
+
+// Idc=Im/%pi and Vdc=Idc*Rl so
+// Vdc=(Im/%pi)*Rl .Also Im*Rl=Vsm so
+Vdc=Vsm/%pi
+
+// in negative half cycle diode is reverse biased so maximum secondary voltage appears across diode.
+PIV=Vsm
+
+printf("output dc voltage = %.2f V \n",Vdc)
+printf("peak inverse voltage = %.2f V \n",PIV)
+
+// accurate answer for output dc voltage is 10.35 V not 10.36 V
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