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+//chapter4
+//example4.1
+//page68
+
+rp=300 // ohm
+Rl=1200 // ohm
+
+Vm=200*2^0.5 //V
+Im=Vm/(rp+Rl)
+Idc=Im/%pi // in ampere
+Idc_mA=Idc*1000 // in mA
+Irms=Im/2
+Irms_mA=Irms*1000
+Pdc=Idc^2*Rl
+Pac=Irms^2*(rp+Rl)
+efficiency=(Pdc/Pac)*100
+
+printf("dc current = %.3f A or %.3f mA \n",Idc,Idc_mA)
+printf("rms current = %.3f A or %.3f mA \n",Irms,Irms_mA)
+printf("rectification efficiency = %.2f percentage",efficiency)
+
+// accurate answer of rms current is 94.281 mA but in book it is given as 94.5 mA