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+//chapter3
+//example3.1
+//page41
+
+Ib1=10 // mA
+Eb1=100 // V
+Ib2=20 // mA
+
+// Ib is proportional to Eb^(3/2)
+// so we can say Ib1/Ib2 = Eb1^1.5/Eb2^1.5
+//thus we can write
+
+log_Eb2=(2/3)*log(Eb1^1.5*Ib2/Ib1)
+Eb2=exp(log_Eb2)
+printf("required plate voltage = %.3f V",Eb2)