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+//chapter 14
+//example 14.7
+//page 302
+
+Ao_db=70 // db
+Av_db=67 // db
+Rout=1.5 // kilo ohm
+
+// since 20*log(Ao)-20*log(Av)=Ao_db-Av_db we get
+// 20*log(Ao/Av) = Ao_db-Av_db so
+// Ao/Av = 10^((Ao_db-Av_db)/20) 
+// and also Ao/Av=1+Rout/Rl since Av/Ao=Rl/(Rl+Rout)
+
+// so making Rl as subject we get
+Rl=Rout/(10^((Ao_db-Av_db)/20)-1)
+
+printf("minimum value of load resistance = %.3f kilo ohm \n",Rl)
+
+// the accurate answer is 3.636 kilo ohm