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Diffstat (limited to '2459/CH14/EX14.16')
| -rw-r--r-- | 2459/CH14/EX14.16/Ex14_16.PNG | bin | 0 -> 5703 bytes | |||
| -rw-r--r-- | 2459/CH14/EX14.16/Ex14_16.sce | 16 |
2 files changed, 16 insertions, 0 deletions
diff --git a/2459/CH14/EX14.16/Ex14_16.PNG b/2459/CH14/EX14.16/Ex14_16.PNG Binary files differnew file mode 100644 index 000000000..c95526748 --- /dev/null +++ b/2459/CH14/EX14.16/Ex14_16.PNG diff --git a/2459/CH14/EX14.16/Ex14_16.sce b/2459/CH14/EX14.16/Ex14_16.sce new file mode 100644 index 000000000..34b02f332 --- /dev/null +++ b/2459/CH14/EX14.16/Ex14_16.sce @@ -0,0 +1,16 @@ +// chapter14
+// example14.16
+// page 312
+
+Vp=10 // V
+// for maximum power transfer, primary impedence = output impedence of aource
+Rp=10d3 // ohm
+Rs=16 // ohm
+
+// since Rp=(Np/Ns)^2*Rs, making Np/Ns i.e. n as subject we get
+n=(Rp/Rs)^(0.5)
+
+// since Vs/Vp=Ns/Np, making Vs as subject we get
+Vs=(1/n)*Vp
+printf("required turn ratio = %d \n",n)
+printf("voltage across external load = %.3f V \n",Vs)
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