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+//chapter13
+//example13.8
+//page282
+
+del_Ib=10d-3 // mA
+del_Ic=1 // mA
+del_Vbe=0.02 // V
+Rc=5 // kilo ohm
+Rl=10 // kilo ohm
+
+Ai=del_Ic/del_Ib
+Rin=del_Vbe/del_Ib
+R_AC=Rc*Rl/(Rc+Rl)
+Av=Ai*R_AC/Rin
+Ap=Av*Ai
+
+printf("current gain = %.3f \n",Ai)
+printf("input impedence = %.3f kilo ohm \n",Rin)
+printf("ac load = %.3f kilo ohm \n",R_AC)
+printf("voltage gain = %.3f \n",Av)
+printf("power gain = %.3f \n",Ap)
+
+// the accurate answer for voltage gain = 166.667 and for power gain = 16666.667 but in book they are given as 165 and 16500 respectively.