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+//chapter11
+//example11.7
+//page206
+
+Vbe=0.7 // V
+Vcc=18 // V
+Vee=8 // V
+Rc=1.2 // kilo ohm
+Re=1.5 //kilo ohm
+
+// by Kirchoff's voltage law to emitter side loop, we get Vee=Ie*Re+Vbe so
+Ie=(Vee-Vbe)/Re
+Ic=Ie // nearly
+
+// by Kirchoff's voltage law to collector side loop, we get Vcc=Ic*Rc=Vcb so
+Vcb=Vcc-Ic*Rc
+
+printf("collector curent  = %.3f mA \n",Ic)
+printf("collector base voltage = %3f V \n",Vcb)