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+// Exa 1.6
+clc;
+clear;
+close;
+format('v',9)
+// Given data
+l = 1;// in cm
+l = l * 10^-2;// in m
+A = 1;// in mm^2
+A = A * 10^-6;// in m^2
+R = 100;// in ohm
+rho = (R*A)/l;// in ohm-m
+sigma = 1/rho;
+e = 1.6*10^-19;// in C
+miu_e = 1350;// in cm^2/V-s
+miu_e = miu_e * 10^-4;// in m^2/V-s
+n = sigma/(e*miu_e);// in /m^3
+disp(n,"The dopant density in /m^3");
+
+// Note: The unit of the answer is wrong because 0.0463*10^23/m^3 = 4.63*10^21/m^3, not in /cm^3