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diff --git a/2417/CH8/EX8.11/Ex8_11.sce b/2417/CH8/EX8.11/Ex8_11.sce new file mode 100755 index 000000000..a1958f4a0 --- /dev/null +++ b/2417/CH8/EX8.11/Ex8_11.sce @@ -0,0 +1,41 @@ +//scilab 5.4.1
+clear;
+clc;
+printf("\t\t\tProblem Number 8.11\n\n\n");
+// Chapter 8 : Vapor Power Cycles
+// Problem 8.11 (page no. 394)
+// Solution
+
+printf("Solution for (a)\n");
+//For the rankine cycle,the Mollier chart gives
+h4=1505; //Enthalpy //Unit:Btu/lbm
+h5=922; //Enthalpy //Unit:Btu/lbm
+h6=h5; //Enthalpy //Unit:Btu/lbm
+//and at the condenser,
+h1=69.74; //enthalpy //Unit:Btu/lbm
+nR=(h4-h5)/(h4-h1); //efficiency of rankine cycle
+printf("The efficiency of rankine cycle is %f percentage\n\n",nR*100);
+
+printf("Solution for (b)\n");
+//Figure 8.16 shows the regenerative cycle.After doing work(isentropically),W lbs of steam are bled from the turbine at 50 psia for each lbm of steam leaving the steam generator,and (1-W) pound goes through the turbine and is condensed in the condenser to saturated liquid at 1 psia.This condensate is pumped to the heater,where it mixes with the extraced steam and leaves as saturated liquid at 50 psia.The required enthalpies are:
+//Leaving turbine:
+h5=1168; //Btu/lbm at 50 psia
+//Leaving condenser:
+h7=69.74; //Btu/lbm at 1 psia // is equal to h8 if pump work is neglected
+//Leaving heater:
+h1=250.24; //Btu/lbm at 50 psia //is equal to h2 if pump work is neglected(saturated liquid)
+//A Heat balance around the heater gives
+//W*h5 + (1-W)*h7 = 1*h1
+W=((1*h1)-h7)/(h5-h7); //Unit:lbm //W lb of steam
+printf("W=%f lbm\n",W);
+work=(1-W)*(h4-922) + W*(h4-h5); //h5=922 from the mollier chart //Unit:Btu/lbm //The work output
+printf("The work output is %f Btu/lbm\n",work);
+//Heat into steam generator equals the enthalpy leaving minus the enthalpy of the saturated liquid entering at 50 psia:
+qin=h4-h1; //Unit:Btu/lbm //Heat in
+n=work/qin; //Efficiency of regenerative cycle
+printf("The efficiency of regenerative cycle is %f percentage\n",n*100);
+//The efficiency of a regenerative cycle with one open heater is given by
+n=1-(((h5-h1)*(h6-h7))/((h4-h1)*(h5-h7))); //efficiency of a regenerative cycle
+W=(h1-h7)/(h5-h7); //Unit:lbm //W lb of steam
+printf("When the rankine cycle is compared with regenerative cycle,\n");
+printf("W=%f lbm and the efficiency of a regenerative cycle with one open heater is given by %f percentage\n",W,n*100);
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