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+clear;
+clc;
+printf("\t\t\tProblem Number 6.35\n\n\n");
+// Chapter 6: The Ideal Gas
+// Problem 6.35 (page no. 285) 
+// Solution
+
+//In this problem,the air expands from 5 atm absolute to 1 atm absolute from an initial temperature of 1000R,
+pr=12.298; //relative pressure //unit:atm 
+h=240.98; //Btu/lbm //enthalpy 
+pr=12.298/5; //The value of the final relative pressure //unit:atm
+//Interpolation in the air table yields the following:
+//   T     pr
+//  620   2.249
+//        2.4596
+//  640   2.514
+T=620+(((2.4596-2.249)/(2.514-2.249))*20); //the final temperature //unit:R
+printf("The absolute final temperature is %f R\n",T);
+u1=172.43; //initial internal energy //Btu/lbm
+u2=108.51; //final internal energy //Btu/lbm
+work=u1-u2; //Btu/lbm The work done by air in an isentropic nonflow expansion //where the value of u2 is obtained by interpolation at T  temperature and the value of u1 is read from the air table at 1000 R. 
+printf("The work done by air in an isentropic nonflow expansion is %f Btu/lbm(out)\n",work)