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Diffstat (limited to '2417/CH6/EX6.26')
| -rwxr-xr-x | 2417/CH6/EX6.26/Ex6_26.sce | 21 |
1 files changed, 21 insertions, 0 deletions
diff --git a/2417/CH6/EX6.26/Ex6_26.sce b/2417/CH6/EX6.26/Ex6_26.sce new file mode 100755 index 000000000..7bf02f2fd --- /dev/null +++ b/2417/CH6/EX6.26/Ex6_26.sce @@ -0,0 +1,21 @@ +clear;
+clc;
+printf("\t\t\tProblem Number 6.26\n\n\n");
+// Chapter 6: The Ideal Gas
+// Problem 6.26 (page no. 270)
+// Solution
+
+//data given
+v2=2; //Because,v2=(2)*v1 //volume increases to its twice its final volume
+v1=1; //initial volume
+T=460+200; //Fahrenheit temperature converted to absolute temperature
+J=778; //conversion factor
+R=1545/28; //moleculer weight of nitrogen=28 //Unit:ft*lbf/lbm*R //constant of proportionality
+//From the equation, w/J=q=T*deltas=((R*T)/J)*log(v2/v1)
+q=((R*T)/J)*log(v2/v1); //Btu/lbm //the heat added to system
+//For 0.1 lb,
+Q=0.1*q; //Btu //the heat added to system
+printf("The heat added to system is %f Btu\n",Q);
+//The work out of the system is equal to the heat added;thus,
+WbyJ=Q; //The work out of the system(out of the system) //unit:Btu
+printf("The work out of the system is %f Btu(out of the system)\n",WbyJ);
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