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+clear;
+clc;
+printf("\t\t\tProblem Number 6.16\n\n\n");
+// Chapter 6: The Ideal Gas
+// Problem 6.16 (page no. 260)
+// Solution
+
+//data
+cp=0.24; //Specific heat at constant pressure //Btu/lbm*R
+p2=15; //psia //final pressure
+p1=100; //psia //initial pressure
+T2=460+0; //absolute final temperature //unit:R
+T1=460+100; //absolute initial temperature //unit:R
+J=778; //conversion factor
+R=1545/29; //moleculer weight=29 //Unit:ft*lbf/lbm*R //constant of proportionality
+ //On the basis of the data given,
+deltas=(cp*(log(T2/T1)))-((R/J)*(log(p2/p1))); //change in entropy //Btu/lbm*R
+printf("The change in enthalpy is %f Btu/lbm*R\n",deltas);