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+//scilab 5.4.1
+clear;
+clc;
+printf("\t\t\tProblem Number 5.7\n\n\n");
+// Chapter 5 : Properties Of Liquids And Gases
+// Problem 5.7 (page no. 192)
+// Solution
+
+//Using Table 2 ans a quality of 80%(x=0.8),we have
+//at 120 psia
+x=0.8;
+sf=0.49201; //saturated liquid entropy //Unit:Btu/lbm*R
+sfg=1.0966; //Evap. Entropy //Unit:Btu/lbm*R
+hf=312.67; //saturated liquid enthalpy //Unit:Btu/lbm
+hfg=878.5; //Evap. Enthalpy //Unit:Btu/lbm
+uf=312.27; //saturated liquid internal energy //Unit:Btu/lbm
+ufg=796.0; //Unit:Btu/lbm //Evap. internal energy
+vf=0.017886; //Saturated liquid specific volume //Unit:ft^3/lbm
+vfg=(3.730-0.017886); //evap. specific volume //Unit:ft^3/lbm
+sx=sf+(x*sfg); //entropy //Btu/lbm*R
+printf("Entropy of a wet steam mixture at 120 psia is %f Btu/lbm*R\n",sx);
+hx=hf+(x*hfg); //enthalpy //Btu/lbm*R
+printf("Enthalpy of a wet steam mixture at 120 psia is %f Btu/lbm\n",hx);
+ux=uf+(x*ufg); //internal energy //Btu/lbm*R
+printf("Internal energy of a wet steam mixture at 120 psia is %f Btu/lbm\n",ux);
+vx=vf+(x*vfg); ///specific volume //ft^3/lbm
+printf("Specific Volume of a wet steam mixture at 120 psia is %f ft^3/lbm\n",vx);
+//As a check,
+J=778; //ft*lbf/Btu //Conversion factor
+px=120; //psia //pressure
+ux=hx-((px*vx*144)/J); //1 ft^2=144 in^2 //internal energy
+printf("As a check,\n")
+printf("Internal energy of a wet steam mixture at 120 psia is %f Btu/lbm\n",ux);
+printf("Which agrees with the values obtained above");