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+//scilab 5.4.1
+clear;
+clc;
+printf("\t\t\tProblem Number 5.4\n\n\n");
+// Chapter 5 : Properties Of Liquids And Gases
+// Problem 5.4  (page no. 189) 
+// Solution
+
+//By defination,
+//hg=ug+(p*vg)/J
+//hf=uf+(p*vf)/J
+//hfg = hg-hf = (ug-uf) + p*(vg-vf)/J = ufg + p*(vg-vf)/J
+//From table 2 at 115 psia,
+p=115; //Unit:psia //absolute pressure
+ufg=798.8; //Unit:Btu/lbm //Evap. internal energy
+ug=3.884; //Unit:ft^3/lbm //Saturated vapour internal energy
+vf=0.017850; //Unit:ft^3/lbm //Saturated liquid specific volume
+J=778; //J=Conversion factor //Unit:ft*lbf/Btu
+//1 ft^2=144 in^2
+hfg=ufg+(p*144*(ug-vf))/J; //Evap. Enthalpy //Unit:Btu/lbm
+printf("hfg for saturated steam at 115 psia is %f Btu/lbm",hfg); //The tabulated values are matched