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+//scilab 5.4.1
+clear;
+clc;
+printf("\t\t\tProblem Number 11.5\n\n\n");
+// Chapter 11 : Heat Transfer
+// Problem 11.5  (page no. 558) 
+// Solution
+
+printf("In problem 11.4,\n");
+//From example 11.4,,,
+//For Brick,
+deltaX=6/12; //6 inch = 6/12 feet //deltaX=length //unit:ft
+A=1; //area  //unit:ft^2
+k=0.40; //Unit:Btu/(hr*ft*F) //k=proportionality constant //k=thermal conductivity //From the table
+R=deltaX/(k*A); //Thermal resistance //Unit:(hr*f)/Btu
+printf("For brick,\n");
+printf("The resistance is %f (hr*F)/Btu\n\n",R);
+R1=R;
+
+//For Concrete,
+deltaX=(1/2)/12; //(1/2) inch = (1/2)/12 feet //deltaX=length //unit:ft
+A=1; //area //ft^2
+k=0.80; //Unit:Btu/(hr*ft*F) //k=proportionality constant //k=thermal conductivity //From the table
+R=deltaX/(k*A); //Thermal resistance //Unit:(hr*f)/Btu
+printf("For Concrete,\n");
+printf("The resistance is %f (hr*F)/Btu\n\n",R);
+R2=R;
+
+//For plaster,
+deltaX=(1/2)/12; // (1/2) inch = 6/12 feet //deltaX=length //unit:ft
+A=1; //area //ft^2
+k=0.30; //Unit:Btu/(hr*ft*F) //k=proportionality constant //k=thermal conductivity //From the table
+R=deltaX/(k*A); //Thermal resistance //Unit:(hr*f)/Btu
+printf("For plaster,\n");
+printf("The resistance is %f (hr*F)/Btu\n\n",R);
+R3=R;
+
+Rot=R1+R2+R3; //Rot=The overall resistance //unit:(hr*F)/Btu
+printf("The overall resistance is %f (hr*F)/Btu\n\n",Rot);
+T1=70; //temperature maintained at one face //fahrenheit 
+T2=30; //tempetature maintained at other face //fahrenheit 
+deltaT=T2-T1; //fahrenheit //Change in temperature
+Q=deltaT/Rot; //Q=Heat transfer //Unit:Btu/(hr*ft^2);
+printf("Heat transfer per square foot of wall is %f Btu/hr*ft^2",abs(Q));
+
+printf("Now in problem 11.5,\n");
+deltaT=R*Q //ohm's law (fourier's equation) //Change in temperature //fahrenheit
+//For Brick,
+deltaT=Q*R1; //Unit:fahrenheit //ohm's law (fourier's equation) //Change in temperature
+t1=deltaT;
+//For Concrete,
+deltaT=Q*R2; //Unit:fahrenheit //ohm's law (fourier's equation) //Change in temperature
+t2=deltaT;
+//For plaster,
+deltaT=Q*R3; //Unit:fahrenheit //ohm's law (fourier's equation) //Change in temperature
+t3=deltaT;
+
+deltaTo=t1+t2+t3; //Overall Change in temperature //fahrenheit
+printf("The overall change in temperature is %f F\n",abs(deltaTo));
+//The interface temperature are:
+printf("The interface temperature are:\n");
+printf("For brick-concrete : %f fahrenheit\n",abs(T2)+abs(t1));
+printf("For concrete-plaster : %f fahrenheit\n",abs(T2)+abs(t1)+abs(t2));