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+//scilab 5.4.1
+clear;
+clc;
+printf("\t\t\tProblem Number 11.27\n\n\n");
+// Chapter 11 : Heat Transfer
+// Problem 11.27  (page no. 605) 
+// Solution
+
+//HEAT EXCHANGER
+//Oil flows in the tube side and is cooled from  280 F to 140 F
+//Therefore,
+t2=140; //Unit:fahrenheit
+t1=280; //Unit:fahrenheit
+//On the shell side,water is heated from 85 F to 115 F
+T1=85; //Unit:fahrenheit
+T2=115; //Unit:fahrenheit
+P=(t2-t1)/(T1-t1); 
+R=(T1-T2)/(t2-t1);
+//From the figure,
+F=0.91;//Correction factor
+LMTD=((t1-T2)-(t2-T1))/log((t1-T2)/(t2-T1)); //LMTD=Log mean temperature difference //Unit:fahrenheit
+TMTD=F*LMTD; //TMTD=True mean temperature difference //Unit:fahrenheit
+printf("The true mean temperature is %f fahrenheit",TMTD);
+