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+//scilab 5.4.1
+clear;
+clc;
+printf("\t\t\tProblem Number 11.24\n\n\n");
+// Chapter 11 : Heat Transfer
+// Problem 11.24  (page no. 601) 
+// Solution
+
+//A COUNTERFLOW HEAT EXCHANGER
+//Hot oil enters at 215 F and leaves at 125 F
+//Water enters the unit at 60 F and leaves at 90 F
+//Therefore,From figure 11.34, 
+thetaA=215-90; //the greatest temperature difference between the fluids(at either inlet or outlet) //Unit:fahrenheit
+thetaB=125-60; //the least temperature difference between the fluids(at either inlet or outlet) //Unit:fahrenheit
+deltaTm=(thetaA-thetaB)/log(thetaA/thetaB); //logarithmic mean temperature difference //Unit:fahrenheit 
+//From the oil data,
+m=400*60;  //mass //Unit:lb/sec //1 min=60 sec
+Cp=0.85; //Specific heat of the oil //Unit:Btu/(lb*F)
+deltaT=215-125;  //Change in temperature //Unit:fahrenheit
+Q=m*Cp*deltaT //The heat transfer //Unit:Btu/hr
+//Q=U*A*deltaTm
+U=40;//The overall coefficient of heat transfer of the unit //Unit:Btu/(hr*ft^2*F)
+A=Q/(U*deltaTm); //Umit:ft^2 //The outside surface area
+printf("The outside surface area required is %f ft^2",A);
+