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+//scilab 5.4.1
+clear;
+clc;
+printf("\t\t\tProblem Number 10.7\n\n\n");
+// Chapter 10 : Refrigeration
+// Problem 10.7  (page no. 510) 
+// Solution
+ 
+//From Appendix 3,110 psig corresponds to 96 F, enthalpies are
+h1=30.14; //Unit:Btu/lbm //enthalpy
+h2=30.14; //Unit:Btu/lbm //Throttling gives h1=h2 //enthalpy
+h3=75.110; //Unit:Btu/lbm //enthalpy
+//From the consideration that s3=s4,at -20F,
+s3=0.17102; //Unit:Btu/(lbm*F) //s=entropy
+//Therefore by interpolation in the Freon-12 superheat table at these values,
+h4=89.293; //Unit:Btu/lbm //enthalpy
+printf("Solution for (a),\n");
+COP=(h3-h1)/(h4-h3); //Coefficient of performance
+printf("Coefficient of performance is %f\n\n",COP);
+printf("Solution for (b),\n");
+printf("The work of compression is %f Btu/lbm\n\n",h4-h3);
+printf("Solution for (c),\n");
+printf("The refrigatering effect is %f Btu/lbm\n\n",h3-h1);
+printf("Solution for (d),\n");
+tons=30; //capacity of 30 tons is desired
+printf("The pounds per minute of ammonia required for ciculation is %f lbm/min\n\n",(200*tons)/(h3-h1));
+printf("Solution for (e),\n");
+printf("The ideal horsepower per ton of refrigeration is %f hp/ton\n\n",4.717*((h4-h3)/(h3-h1)));
+
+