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+// Exa 10.8
+clc;
+clear;
+close;
+format('v',6)
+// Given data
+A = 100;
+Beta = 1/25;
+Af = A/(1 + (A*Beta));
+disp(Af,"The gain with feedback is");
+disp((A*Beta),"The feed back factor is");
+Vi = 50;// in mV
+Vo =Af*Vi*10^-3;// in V
+disp(Vo,"The output voltage in V is");
+V_feedback= (Beta*Vo);// feedback voltage in V
+disp(V_feedback,"The feed back voltage in V is");
+Vi = Vi*(1+(A*Beta));// in mV
+disp(Vi,"The new input voltage in mV is");