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+//Finding loss
+//Example 6.4(pg 214)
+clc
+clear
+Hl=250//Hysteresis loss per m^3 in J/cycle
+V=1/150//Volume of specimen in m^3
+N=50//No of cycles/sec
+E=Hl*V*N//Energy loss per sec in J
+Eh=(E*3600)/1000//Energy loss per hour in kWh
+printf('Thus Energy loss per hour is %3.2f kWh',Eh)