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+//Finding current
+//Example 15.40(pg. 418)
+clc
+clear
+phi=70000/(10^8)//flux to be set up in Wb since 10^8lines =1Wb
+d=0.03//diameter in m
+a=%pi*d*d/4//area of cross section in m^2
+B=phi/a//flux density in Wb/m^2
+Lg=0.002//length of air gap in m
+Ls=(%pi*0.2)-Lg//length of steel path
+Uo=4*%pi*(10^-7)//absolute permitivity
+Ur=800//relative permitivity of steel
+Hg=B/Uo
+Hs=B/(Uo*Ur)
+AT=(Hg*Lg)+(Hs*Ls)//total ampere turns required 
+N=500// no of turns
+I=AT/N//exciting current in amps
+printf('Thus the value of exciting current is %2.3f A',I)