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+//Finding inductance and energy
+//Example 15.23(pg. 407)
+clc
+clear
+l=0.5//length of coil in meters
+d=0.1//diameter of coil
+N=1500//no of turns of coil
+a=%pi*(d^2)/4//cross sectional area of coil in m^2
+Ur=1//relative permeability
+Uo=4*%pi*(10^-7)//permeability
+I=8//current in A
+L=((N^2)*a*Uo*Ur)/l//self inductance of coil in H
+E=(1/2)*L*(I^2)//Energy stored in Joules
+printf('Thus Self Inductance of coil is %2.3f H\n',L)
+printf('and Energy stored is %1.2f Joules',E)