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+//Calculate horizontal component of tension and max sag
+clear;
+clc;
+//soltion
+//given
+W=750;//kg/km//Line conductor weight
+L=300;//meter//span of the line
+T=3400;//kg//max allowable tension
+w=W/1000;//kg/m//Weight of conductor in meter
+printf("Max sag= (W*L^2)/(8*Th)\n");
+x= (w*L^2)/(8);
+printf("Sag= %.1f/Th\n\n",x);
+printf("Max tension= Th + wS\n");
+Th=(T+sqrt(T^2+4*w*x))/2;
+printf("Horizontal component of tension (Th)= %.3f kg\n",Th);
+sag= (w*L^2)/(8*Th);
+printf("Sag= %.3f m\n",sag);
+y=sag/2;
+z=sqrt((2*Th*y)/w);
+printf("Point at which sag will be half= %.3f m\n", z);
+//THERE IS TYPOGRAPHICAL ERROR IN BOOK DUE TO THAT THERE IS A VARIATION
+//IN BOOK Th=3448.191 kg
+//MAX SAG=2.446 m
+//Point at which sag will be half= 106.045 m