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+clc();
+clear;
+// To calculate the ratio between electronic and ionic polarizability
+epsilon_r=4.94;
+N=2.69; //let n^2 be N
+//(epsilon_r-1)/(epsilon_r+2) = (N*alpha)/(3*epsilon_0)
+//alpha = alpha_e+alpha_i
+//therefore (epsilon_r-1)/(epsilon_r+2) = (N*(alpha_e+alpha_i))/(3*epsilon_0)
+//let (N*(alpha_e+alpha_i))/(3*epsilon_0) be X
+X=(epsilon_r-1)/(epsilon_r+2);
+//Ez=n^2
+//therefore (N-1)/(N+2) = (N*alpha_e)/(3*epsilon_0)
+//let (N*alpha_e)/(3*epsilon_0) be Y
+Y=(N-1)/(N+2);
+//dividing X/Y = (N*(alpha_e+alpha_i))/(N*alpha_e)
+//therefore X/Y = 1+(alpha_i/alpha_e)
+//let alpha_i/alpha_e be A
+R=(X/Y)-1;
+printf("ratio between electronic and ionic polarizability is %f",R);
+
+//answer given in the book is wrong in the second part