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+// Grob's Basic Electronics 11e
+// Chapter No. 25
+// Example No. 25_4
+clc; clear;
+// What value of L resonates with a 106-pF C at 1000 kHz, equal to 1 MHz?
+
+// Given data
+
+C = 106*10^-12; // Capacitor=106 pFarad
+fr = 1*10^6; // Resonant frequency=1 MHertz
+
+A = %pi*%pi; // pi square
+B = fr*fr; // Resonant frequency square
+
+C = 1/(4*A*B*C);
+disp (C,'The value of Inductor in Henry')
+disp ('i.e 239 uF')