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+// Grob's Basic Electronics 11e
+// Chapter No. 09
+// Example No. 9_1
+clc; clear;
+// Apply Kirchhoff’s current law to solve for the unknown current, I3.
+
+// Given data
+
+I1 = 2.5; // Branch 1 Current=2.5 Amps
+I2 = 8; // Branch 2 Current=8 Amps
+I4 = 6; // Branch 3 Current=6 Amps
+I5 = 9; // Branch 4 Current=9 Amps
+
+// I1+I2+I3-I4-I5 = 0 Sum of all currents at node is ZERO
+// I1+I2+I3 = I4+I5 Total Incomming Current = Total Outgoing Current
+
+I3 = I4+I5-I1-I2;
+disp (I3,'The Branch 3 Current I3 in Amps')