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+// problem 5.4
+x=90
+H=0.2
+b=0.3
+Cd=0.62
+g=9.81
+q1=(8*Cd*tand(x/2)*((2*g)^0.5)*(H^2.5))/15
+q2=2*Cd*b*((2*g*H*H*H)^0.5)/3
+q=q1+q2
+disp(q,"discharge over the trapezoidal notch in m3/sec")