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+
+clc
+//initialisation of variables
+T1=520 //R
+P1=14.7 //lbf/in^2
+v1=(53.34*T1)/(P1*144)//ft^3/lbm
+T=2.3 //lbf
+T2=T*T1//R
+P2=18.4*(P1)//lbf/in^2
+v2=v1/8 //ft^3/lbm
+Q=800 //Btu/lbm
+T3=Q/0.171 //R
+T4=T2+T3//R
+T5=4.92 //R
+T6=T5*P2//lbf/in^2
+t=T4/T//R
+p=18.4 //lbf/in^2
+p1=T6/p//lbf/in^2
+nth=0.565 //btu/lbm
+Cv=0.171 //Btu
+g=144//ft
+T=778//f
+//CALCULATIONS
+Q1=Cv*(T1-t)//Btu/lbm
+Nth=1-(-Q1/Q)//Btu/lbm
+Wnet=Q+Q1 //Btu/lbm
+Mep=(Wnet*T)/((v1-v2)*g)//lbf/in^2
+//RESULTS
+printf('The pressure and thermal efficiency and the mean efficiency pressure=% f lbf/in^2',Mep)