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+//Exa 2.25
+clc;
+clear;
+close;
+format('v',7);
+
+//Given Data : 
+m=1.5;//Kg
+p1=1000;//Kpa
+p2=200;//Kpa
+V1=0.2;//m^3
+V2=1.2;//m^3
+//p=a+b*v
+//solving for a and b by matrix
+A=[1 V1;1 V2];
+B=[p1;p2];
+X=A^-1*B;
+a=X(1);
+b=X(2);
+W=integrate('a+b*V','V',V1,V2);//KJ/Kg
+disp(W,"Work transfer in KJ/Kg : ");
+u2SUBu1=(1.5*p2*V2+35)-(1.5*p1*V1+35);//KJ/Kg
+disp(u2SUBu1,"Change in internal energy in KJ/Kg : ");
+q=W+u2SUBu1;//KJ/Kg
+disp(q,"Heat transfer in KJ/Kg : ");
+//u=1.5*(a+b*V)*V+35;
+//1.5*a+2*V*1.5*b=0;//for max value putting du/dV=0
+V=-1.5*a/2/1.5/b;//m^3/Kg
+p=a+b*V;//KPa
+u_max=1.5*p*V+35;//KJ/Kg
+disp(u_max,"Maximum internal energy in KJ/Kg : ");
+//Answer in the book is wrong because a is 1160 instead of 1260.