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+//To find power absorbed in friction
+clc
+//Given:
+n=6
+d1=600,r1=d1/2,d2=300,r2=d2/2 //mm
+W=100*1000 //N
+mu=0.12
+N=90 //rpm
+//Solution:
+//Calculating the angular speed of the engine
+omega=2*%pi*N/60 //rad/s
+//Power absorbed in friction assuming uniform pressure:
+//Calculating the total frictional torque transmitted
+T=2/3*mu*W*(r1^3-r2^3)/(r1^2-r2^2)/1000 //N-m
+//Calculating the power absorbed in friction
+P1=T*omega/1000 //Power absorbed in friction assuming uniform pressure, kW
+//Power absorbed in friction assuming uniform wear:
+//Calculating the total frictional torque transmitted
+T=1/2*mu*W*(r1+r2)/1000 //N-m
+//Calculating the power absorbed in friction
+P2=T*omega/1000 //Power absorbed in friction assuming uniform wear, kW
+//Results:
+printf("\n\n Power absorbed in friction assuming uniform pressure, P = %.1f kW.\n",P1)
+printf(" Power absorbed in friction assuming uniform wear, P = %.2f kW.\n\n",P2) \ No newline at end of file