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+// Exa 3.7
+clc;
+clear;
+close;
+// Given data
+n=2;
+V_T=26;// in mV
+Io= 30;// in mA
+// (i) when
+I_D= 0.1;// in mA
+V_D= n*V_T*log(I_D/Io);// in mV
+disp(V_D,"(i) When I_D is 0.1 mA, The junction forward-bias voltage in mV is : ")
+// (ii) when
+I_D= 10;// in mA
+V_D= n*V_T*log(I_D/Io);// in mV
+disp(V_D,"(ii) When I_D is 10 mA, The junction forward-bias voltage in mV is : ")
+
+// Note: There is calculation error in the book so answer in the book is wrong.