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+// Exa 3.6
+clc;
+clear;
+close;
+// Given data
+J=10^4;// in A/m^2
+Jo=200;// in mA/m^2
+Jo= Jo*10^-3;// in A/m^2
+T=300;// in K
+V_T= T/11600;// in V
+e=1.6*10^-19;// electrone charge
+k= 1.38*10^-23;
+n=1;// assuming value
+//Formula I= Io*(%e^(e*V/(n*k*T))-1) and after dividing both the sides by area of the junction, we have
+// J= Jo*(%e^(e*V/(n*k*T)));// approx by neglecting 1 
+V= n*k*T*log(J/Jo)/e;
+disp(V,"Voltage to be applied across the junction in volt is")
+
+// Note:- In the book, the value of T (i.e. 300) has not been putted to evaluate the value of V. So if we'll not put the value of T to evaluate the value of V, then the answer of coding will be same as book. Hence the 
+//              the answer in the book is wrong.