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+// Exa 1.16
+clc;
+clear;
+close;
+// Given data
+q=1.6*10^-19;// in C
+n=4*10^22;// in /m^3
+ni= 2.4*10^19;// in /m^3
+miu_n= 3500;// in cm^2/vs
+miu_n= miu_n*10^-4;// in m^2/vs
+// Formula n*p= ni^2
+p= ni^2/n;// in m^-3
+disp(p,"Hole concentration in m^-3 is : ")
+sigma=q*n*miu_n;// in (Ω-m)^-1
+disp(sigma,"The conductivity of the extrinsic semiconductor in (Ωm)^-1 is :")
+
+// Note : There is miss print in the printed value of p and also calculation error in evaluating the value of p . So the answer in the book is wrong