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+clc
+clear
+//Input data
+C=0.86;//The amount of carbon content in the 1kg of fuel by weight in kg
+H=0.05;//The amount of hydrogen content in the 1kg of fuel by weight in kg
+O=0.02;//The amount of oxygen content in the 1kg of fuel by weight in kg
+S=0.005;//The amount of sulphur content in the 1kg of fuel by weight in kg
+N=0.065;//The amount of nitrogen content in the 1kg of fuel by weight in kg
+E=25;//The amount of excess air supplied in percentage
+o=32;//Molecular weight of the oxygen
+co=44;//Molecular weight of the carbondioxide 
+c=12;//Molecular weight of the carbon
+s=32;//Molecular weight of the sulphur
+so=64;//Molecular weight of sulphur dioxide
+n=28;//Molecular weight of the nitrogen
+
+//Calculations
+o1=(o/c)*C;//The amount of oxygen required for 0.86 kg of carbon in kg
+coa=(co/c)*C;//The amount of carbondioxide produced for 0.86 kg of carbon in kg
+o2=(o/4)*H;//The amount of oxygen required for 0.05 kg of hydrogen in kg
+h2=(36/4)*H;//The amount of water produced for 0.05 kg of hydrogen in kg
+o3=(o/s)*S;//The amount of oxygen required for 0.005 kg of sulphur in kg
+s1=(so/s)*S;//The amount of sulphur dioxide produced for 0.005 kg of sulphur in kg
+To=o1+o2+o3;//Total oxygen required for the complete combustion of fuel in kg
+Tt=To-O;//The amount of oxygen required per kg of fuel for complete combustion theoretically in kg
+As=(Tt*100)/23;//Stoichiometric air/fuel ratio
+as=As*(1+(E/100));//The actual quantity of air supplied per kg of fuel in kg
+o2a=0.23*(E/100)*As;//The oxygen in the excess air in kg
+n2a=0.77*(1+(E/100))*As;//The nitrogen in the air in kg
+n2e=n2a+N;//Total nitrogen in the exhaust in kg
+Tw=coa+n2e+o2a;//Total weight in kg
+pco=(coa/Tw)*100;//Percentage composition of carbondioxide
+pn=(n2e/Tw)*100;//Percentage composition of nitrogen
+po=(o2a/Tw)*100;//Percentage composition of oxygen
+mco=(coa/co);//Moles of carbondioxide
+mn=(n2e/n);//Moles of nitrogen
+mo=(o2a/o);//Moles of oxygen
+Tm=mco+mn+mo;//Total moles
+vco=(mco/Tm)*100;//Volumetric analysis of carbondioxide in percentage
+vn=(mn/Tm)*100;//Volumetric analysis of nitrogen in percentage
+vo=(mo/Tm)*100;//Volumetric analysis of oxygen in percentage
+
+//Output
+printf(' (a)Stoichiometric air/fuel ratio = %3.2f \n (b)The percentage of dry products of combustion by weight : \n   CO2 = %3.2f percent \n   N2 = %3.2f percent \n   O2 = %3.2f percent \n (c)The percentage of dry products of combustion by volume : \n   CO2 = %3.2f percent \n   N2 = %3.2f percent \n   O2= %3.2f percent ',As,pco,pn,po,vco,vn,vo)